A block of mass 2 kg is pushed against a rough vertical wall with a force of 40 N, coefficient of static friction being 0.5. Another horizontal force of 15 N, is applied on the block in a direction parallel to the wall. Will the block move? If yes, in which direction? If no, find the frictional force exerted by the wall on the block.
Answers
Imagine this condition in 3-D.
Now, When a Force of 40 N is applied, It will be balanced by the Normal Reaction from the Wall.
When a Force of 15 N is applied, then It may cause Friction.
F net = √[(15)² + (20)²]
⇒ F (net) = √625
⇒ F (net) = 25 N.
This is greater than the 20 N (Friction), therefore, block will move.
∴ Direction = tan⁻¹(15/20)
= tan⁻¹(3/4)
= tan⁻¹ (tan 37)
= 37° with 20 N force, and 53° with 15 N force.
Hope it helps.
Now, When a Force of 40 N is applied, It will be balanced by the Normal Reaction from the Wall.
When a Force of 15 N is applied, then It may cause Friction.
F net = √[(15)² + (20)²]
⇒ F (net) = √625
⇒ F (net) = 25 N.
This is greater than the 20 N(Friction)
∴ block will move.
∴ Direction = tan⁻¹(15/20)
= tan⁻¹(3/4)
= tan⁻¹ (tan 37)
= 37° with a force of 20 N
and 53° with a force of 15 N
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