Question

a block of mass 2 kg is tied with the Rope is going down under the force of gravity of 20 Newton how much force is required by the hand to stop the motion of the block ​

Answer 1

Explanation:

F=ma

F=2*20

F=40N

........

Answer 2

Answer:

The force required to stop the block is  $20N$ .

Explanation:

Given :-
Mass of the block = $20$ KG

Force in downward direction = $20 N$

We know ,

  Force = mass * acceleration .

  $20$ = $2$ * acceleration
 acceleration = $20$/$2$
 acceleration  = $10$ m/$SEC^{2}$

force in upward direction = mass * acceleration
                                          = $2$ * $10$
                                          = $20N$

Therefore the force would required to stop the block is $20$N in upwards direction.

 #SPJ3