a block of mass 2 kg lying on ice ,when given a velocity of 6m/sec is stopped by friction in sec .then the coefficient of friction is
Dhinu:
it stopped by friction in how much sec.??
complete the question please ...
okay
Answers
Answered by
12
Ans. is 0.06 ... solution is in the pic
Attachments:
hehe... you're most welcome! ^_^
Answered by
0
Mass of the marble block, m=2kg. Initial velocity,uo=6m/s. time for velocity to become zero,t=10s
The frictional force=uN=umg. Here u is coefficient of friction. N is normal force of reaction. N=mg.
The retardation( a ) produced by this force=umg/m=ug……………(1). We can find retardation from the equation of motion:
0=uo-at or a=uo/t=6/10=0.6m/s^2…………………………..(2)
From (1) and (2),
ug=0.6. Then u=0.6/10=0.06 .
Similar questions