a block of mass 2 kg moving with a initial velocity of 12m/s comes to rest after 6 sec due to friction. The coefficient of friction between the block and the surface is?
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Answer:
0.2
Explanation:
force of friction, f = 2*(12/6)
=4 N
Normal force ,N= 2*9.8
=19.6N
using formula,
f=u N
u = f/N=4/19.6=0.2
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