Question

A block of mass 2 kg rest on the floor of an elevator. Which is moving down with an acceleration 'g'then,
the apparent weight of the block is take, g = 10 m/s)
​

Answer 1

Answer:

When elevator is accelerating downwards.

Net downward force on the body F=ma

R=mg-ma

=mg-mg=0 (Since, a=g)

Apparent weight becomes zero.

Answer 2

Answer:

0...

Explanation:

Force = F=ma

Weight= R=mg-ma

As a = g So,

R=mg-mg

:., R=0...

Hope it helps you...

Plz mark it as brainliest answer...