A block of mass 2 kg rest on the floor of an elevator.Which is moving down with an acceleration 'g'. Then the apparent weight of the block is? 1. 20N 2. 12N 3. 16N 4 0N
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Answered by
68
Force = F= ma
weight = R = mg-ma
As a=g so,
R=mg-mg
R=0
weight = R = mg-ma
As a=g so,
R=mg-mg
R=0
Answered by
48
m = 2kg
acceleration downwards = a = g
apparent weight = normal reaction from the floor of the elevator
= m g - m a) = 0
acceleration downwards = a = g
apparent weight = normal reaction from the floor of the elevator
= m g - m a) = 0
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