Question

A block of mass 2 kg rests on a rough
inclined plane making an angle of 30° with
the horizontal. If Ms = 0.6, what is the
frictional force on the block ?​

Answer 1

Answer:

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Explanation:

Given that,

Mass of the block, m=2 kg

Angle of inclination between the block and the horizontal line is given as :

θ=30

0

Also,

Coefficient of friction, μ=0.65

The force that tends to slide the body on the inclined plane can be given by,

f=mgsinθ

[A]

F=2×9.8×0.5=9.8N

Answer 2

Explanation:

Given that,

Mass of the block, m=2 kg

Angle of inclination between the block and the horizontal line is given as :

θ=30

0

Also,

Coefficient of friction, μ=0.65

The force that tends to slide the body on the inclined plane can be given by,

f=mg sin θ

[A]

F=2×9.8×0.5=9.8N