Question

A block of mass 2 kg rests on horizontal surface. If a horizontal force of 15 N is applied on the block, the frictional force on, it is (μk = 0.4, μs = 0.5) 5 N 10 N 8 N Zero

Answer 1

Answer:

ANSWER

First calculate the static friction force.

At bottom surface friction coefficient is 0.5

F

1

=μN

1

N

1

=(2+8)g=10×10=100N

Thus,

F

1

=μN

1

=0.5×100N

=50N

Static friction force for motion of lower block we have to apply minimum 50 N force there is no motion until we apply 50 N force.

Thus, there is no motion hence there is no friction force between block A and B.