Question

A block of mass 2 kg rests on the floor of an
elevator which is moving down with an acceleration
8 m/s2. Then the apparent weight of block is (take,
g = 10 ms-2)
(1) 20 N
(2) 12 N
(3) 4N
(4) Zero​

Answer 1

Answer:

4 newton is the answer.........

Answer 2

acceleration = g

apparent weight = m(g-a)

=2(g-g)

=0

it means there is no normal reaction between block and lift so block will feel weightlessness