Question

A block of mass 2 kg slides down an inclined plane of inclination 60 degrees Find the work done by the force of gravity as the block slides through 1m. [Take g=10 ms^ -2 ] .​

Answer 1

Answer:

first the law of work is equal force × displacement

first we will calculate the force

force = mg sin theta

force = 2 × 10 × sin 60 =

$10 \sqrt{3}$

unit N

so the work is

force × displacement =

$10 \sqrt{3} \times 1 = 10 \sqrt{3}$

Unit joule.

Thanks ".