Question

A block of mass 2 kg slides on an inclined plane which makes an angle 30 degree with the horizontal coefficient of friction between the block and the surface is √(3/2) what force should be applied to the block so that the block moves down without
acceleration

Answer 1

Answer:

20.77 N

Explanation:

Mass of block = m = 2 kg (Given)

μ = √(3/2) = 1.225 (Given)

Angle = θ = 30° (Given)

For acceleration to be zero, the force should be provided to balance a  frictional force.

Thus, The frictional force can be calculated as -

F = μmgcosθ

F = 1.225 × 2 × 9.8 × cos30°

F = 20.77 N

Therefore, a force of 20.77 N should be applied to the block so that the block moves down without  an acceleration.