A block of mass 2 kg slides on incline plane with inclination 30 degree and coefficient of friction under 3 by 2 what is the what force should be applied on the block along inclined plane so that it moves without downloads
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Answer- F = 20.77 N
Explanation-
# Given-
m = 2 kg
μ = √(3/2) = 1.225
θ = 30 °
# Solution-
For acceleration to be zero, force should be provided to balance frictional force.
F = μmgcosθ
F = 1.225 × 2 × 9.8 × cos30°
F = 20.77 N
Force of 20.77 N should be applied to get zero acceleration.
Hope it's helpful...
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