A block of mass 20 kg is hung with the help of idealstring, pulleys and spring (Spring constantk = 1000 N/m) as shown in figure. If block is inequilibrium position then extension in the spring willbe (g = 10 ms-2)TO20 kg(1) 10 cmB 5 cm208 (2) 2.5 cm0 (4) 15 cm
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Explanation:
well where is the figure : /
But I'm assuming the only force to be gravitational force
F = mg
= 20 x 10
= 200N
k = 1000 N/m
By Hooke's law,
F = k*x
=> 200 = 1000*x
=> x = 0.2 m
= 20 cm
Hence the extension in the spring will be 20 cm
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