A block of mass 20 kg is moved horizontally from A to B. Work done by gravity is Select an answer A (20) AB B (200)AB C (2000)AB D Zero
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Explanation:
(a)The work done =WD=
F
→
⋅
d
→
Since the force
F
→
and displacement
d
→
are in the same direction.
WD=Fd
Here
F=mgsin53
0
=20⋅10⋅sin53
0
=200⋅0.7986
=159.727N
Hence the work done
F⋅d=159.727⋅4
=638.9J
(b)
From the figure (b)
As the block is in equilibrium.
Net force along the plane=0.
F
1
cos53
0
=mgsin53
0
F
1
=mg⋅tan53
0
The force parallel to plane=F
1
cos53
0
=mgsin53
0
Therefore,
WD=F
1
⋅d
=mgsin53
0
⋅4
=159.727×4
=638.9J
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Explanation:
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