Question

A block of mass 20 kg is pushed with a horizontal force of 90N of the coefficient of static and kinetic friction are 0.4and0.3 the frictional force acting on the block is

Answer 1

mass =29 kg
force= 90N
f s =0.4
fk= 0.3
so,
frictional force is
= fs-fk
= 0.4-0.3
= 0.1
HOPE IT HELPS
THANKS
PLZ MARK BRAINLIEST

Answer 2

Hi friend,

Maximum Static Frictional force = coefficient of static friction * weight
= 0.4 * 20 kg * 10 m/sec² = 80 Newtons (static)
Direction of frictional force is horizontal and is opposite to the direction of 90 Newtons
This is the frictional force until the block starts moving.

When the block starts and is moving:
dynamic or kinetic frictional force = 0.3 * weight = 0.3 * 20 kg * 10 m/s²
= 60 Newtons (in motion)
Direction of frictional force is horizontal and is opposite to the direction of 90 Newtons.