Question

a block of mass 200g dropped from 2m height on to a spring aand compress the spring to distance 59 cm the force constant of spring is

Answer 1

Answer:

,

Explanation:

Here is your answers ,,,

Answer 2

Answer:

Answer

Given data,

Mass of the body is ( m ) =2Kg

spring's constant (K)=1960N/m

height of the body =0.4m

Let the maximum distance spring will compressed =xm

initial potential energy of body =mg(h+x)

final potential energy = spring potential energy =

2

1

Kx

2

according to the law of conservation of energy,

initial potential energy = final potential energy

mg(h+x)=

2

1

Kx

2

2mgh+2mgx=Kx

2

Kx

2

−2mgx−2mgh=0

⇒1960x

2

−2×2×9.8×x−2×2×9.8×0.4=0

⇒1960x

2

−39.2x−15.68=0

after solving this quadratic equations , we get x=0.1m

hence, answer is x=0.1m

Explanation:

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