a block of mass 200g is traveling towards right along a rough horizontal surface at a velocity of 2m/s,while a force 2N is being applied to it towards the right.Predict the value of frictional force acting on it,find the work done by the frictional force when the applied force of 2N ceases to act.
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Explanation:
m = 200g = 1/5 kg
v = 2m/s
F = 2N
frictional force = the force applied
frictional force = 2N
work done = change in kinetic energy
work done = 1/2.mv.v -1/2.m.u.u
work done = 1/2.1/5.0.0 - 1/2.1/5.2.2
work done = 0 - 2/5
work done = -2/5 j
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