Question

a block of mass 20kg is resting on a rough horizontal plane. A horizontal force of 98N is required just to slip the block. find the value of static coefficient and angle of friction? ​

Answer 1

Answer:

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Explanation:

Here , maximum possible value of friction = μmg

= 98 N

We get , coefficient of friction , μ = 0.5.

Now , angle of friction = tan

−1

(μ)

= tan

−1

(0.5)

= 26.56

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