A block of mass 20kg is sitting on a surface inclined at 0=45, Detemin the minimum force necessary to prevent Slipping if the coefficient of static friction is 0.5.
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It's too simple dear and boring too...
Your answer is:-
25 \sqrt{2}252
Actually answer comes from making the body on inclined surface in equilibrium....
This is done by equation :-
mgsin(45°) - 0.5mgcos(45°) = F....
Well love you dear....
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