Physics, asked by galaxy14, 7 months ago

a block of mass 25 kg is lying on a rough horizontal surface when a force of 122.5N is applied horizontally on the surface of the block and the block just begins to move find the coefficient of the friction between the surface and the block.

Answers

Answered by anujtriv2006

0

Answer:

0.49

Explanation:

Equate 122.5N force to limiting friction(cofficient of friction X Normal force on the object)

Normal force will be equAl to mg..

then solve and u will get the answer 4.9/g

I have taken g = 10 so got the answer 0.49

HOPE IT HELPS

PLS MARK AS BRAINLIEST

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