Question

A block of mass 250 g is kept on a vertical spring of spring constant 100 N/m fixed from below. The spring is now compressed 10 cm shorter than its natural length and the system is released from this position. How high does the block rise? Take g = 10 m/s2.

Answer 1

The block rises the height 20 cm.

Explanation:

Given, mass of block m = 250 g

Spring constant k = 100 N/m

Compressed length in spring, x = 10 cm =0.1 m

To calculate the height of block rises, use the conservation of energy

$\frac{1}{2}kx^{2} = mgH$

Here, H is the block rises height and g is acceleration due to gravity.

Substitute the given value in above formula we get

$\frac{1}{2} (100N/m)(0.1m)^{2} =(0.250kg)(10m/s^{2} )H$

$H=\frac{\frac{1}{2} (100N/m)(0.1m)^{2} }{(0.250kg)(10m/s^{2} )}$

$h =0.2 m=20cm$

Thus, the block rises the height 20 cm.

Learn More: Conservation of energy.

https://brainly.in/question/11221627

https://brainly.in/question/3041115

Answer 2

Answer:

hey bro hope u like

Explanation:

The block rises the height 20 cm.

Explanation:

Given, mass of block m = 250 g

Spring constant k = 100 N/m

Compressed length in spring, x = 10 cm =0.1 m

To calculate the height of block rises, use the conservation of energy

Here, H is the block rises height and g is acceleration due to gravity.

Substitute the given value in above formula we get

Thus, the block rises the height 20 cm.

MARK AS BRAINLIST