A block of mass 250 g is on a vertical spring of spring constant 100 N/m fixed from below.The spring is now compressed to have a length 10 cm shorter than its natural length and the system is released from this position. How high does the block rise? Take g=10 m/s².
Concept of Physics - 1 , HC VERMA , Chapter " Work and Energy"
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Given in the question :-
Mass of the block = 250 g. or = 0.25 kg
k = 100 N/m .
Length x = 10 cm = 0.1 m
So here work done on the spring is equal to,
(1/2) kx²
= (1/2) 100 × 0.1²
= 1/2
= 0.5 J.
Assume that the new height of the block be h.
So at the new point Potential energy is equal to ,
= mgh.
Here Potential energy is equal to work done on the spring , Now
mgh = 0.5 J.
0.25 × 10 × h = 0.5
h= 0.5/2.5
h = 0.2 m. or 20 cm
The block rise at the new height of 20 cm.
Hope it Helps.
Mass of the block = 250 g. or = 0.25 kg
k = 100 N/m .
Length x = 10 cm = 0.1 m
So here work done on the spring is equal to,
(1/2) kx²
= (1/2) 100 × 0.1²
= 1/2
= 0.5 J.
Assume that the new height of the block be h.
So at the new point Potential energy is equal to ,
= mgh.
Here Potential energy is equal to work done on the spring , Now
mgh = 0.5 J.
0.25 × 10 × h = 0.5
h= 0.5/2.5
h = 0.2 m. or 20 cm
The block rise at the new height of 20 cm.
Hope it Helps.
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