A block of mass 2kg and density 0.7g/cm is held stationary with the help of a
string. The tank is accelerating vertically down wards with 1 m/s2.(g
= 10 m/s2)
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Answer:
know that
Up thust =Vρ
ω
g
eff
V=
d
M
=
0.8
2000
=2.5×10
3
cc=2.5×10
−3
m
3
ρ
w
=1000kg/m
3
g
eff
=10+1=11 m/s
2
Up thust =2.5×10
−3
×1000×11
=27.5 N
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