Question

A block of mass 2kg is placed over block b of mass 8kg. The combination is placed over a rough horizontal surface. Coefficient of friction between b and the floor is 0.5 coefficient of friction between a and b is 0.4 a horizontal force of 10n is applied on block



b. The force of friction between a and b is

Answer 1

Answer:

1st equation will be f1+f2=10Nf1 force of friction between a and b blockf2 force of friction between b and surfacef1=8Nf2=50NTherefore the force applied 10N is less than the frictional force of 50N. So the block will not move and the friction is limiting friction. And before limiting there is static friction which is a self adjusting force.Static friction is -f1