A block of mass 2kg is resting on a horizontal table . A force of 10 N is applied for 4s on tge block in the horizontal direction .if g =10 metre per second and the coefficient of friction
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Explanation:
friction force= 4N
APPLIED FORCE= 10 N
NET FORCE= 10N-4N= 6N
acceleration of block= 6N/2kg= 3m/s2
distance travelled in 4 second= 24 m
WORK DONE BY APPLIED NET FORCE= 6N X 24m=144J
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