Question

A block of mass 2kg lying on a rough horizontal surface, is given a velocity of 6m/s.
It is stopped by friction in 10s. Then the coefficient of friction is
(g=10 m/s)​

Answer 1

Answer:

• Friction = 0.06

Explanation:

Given that,

• Mass (m) = 2kg
• Final velocity (v) = 6m/s
• Initial velocity (u) = 0m/s
• Time (t) = 10s
• Gravity (g) = 10m/s²

As we know that,

Acceleration = Friction × Gravity

➡ a = μ × g

[ °.° a = (v - u)/t ]

➡ (v - u)/t = μ × g

➡ (6 - 0)/10 = μ × 10

➡ 6/10 = μ × 10

➡ μ = 6/10 × 10

➡ μ = 6/100

➡ μ = 0.06

Hence,

• The coefficient of friction is 0.06.

Answer 2

Explanation:

ᴛʜᴇ ᴄᴏᴇғғɪᴄɪᴇɴᴛ ᴏғ ғʀɪᴄᴛɪᴏɴ ɪs :- 0.06