A block of mass 2kg moving at a speed of 10m/s accelerate at 3m/s² for 5sec. Compute it's final kinetic energy.
Answers
Answered by
129
KINETIC ENERGY IS 0.5*M*V^2
AND V=U+AT
SO V=10+3*5==25
KINETIC ENERGY=0.5×2×25×25
625 JOULES
PLEASE MARK IT BRAINLIEST ANSWER
AND V=U+AT
SO V=10+3*5==25
KINETIC ENERGY=0.5×2×25×25
625 JOULES
PLEASE MARK IT BRAINLIEST ANSWER
Answered by
90
m = 2kg
u = 10m/s
a = 3m/s²
Now,by using first equation of motion,
v = u + at
v = 10 + 3x5
v = 25m/s
(KE)i = 1/2mv²
= 1/2 x 2 x (25)²
= 625 J
u = 10m/s
a = 3m/s²
Now,by using first equation of motion,
v = u + at
v = 10 + 3x5
v = 25m/s
(KE)i = 1/2mv²
= 1/2 x 2 x (25)²
= 625 J
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