A block of mass 2kg placed on a long frictionless table is pulled by a constant force F it is found to move 10m in 1st two seconds find magnitude of F
Answers
Answered by
5
Answer:
since the table is frictionless,there is no opposing frictional force acting upon the block during its motion.
u=0 and t=2s and accn. of block a=F/m=F/2
then,
s=ut+1/2 at2
10=(0)2 +1/2 (F/2)(2)2
F=10N.
Answered by
7
Explanation:
u= 0 and t=2s , m= 2kg
F=ma
a=F/m
a=F/2
s = ut +1/2at^2
10= 1/2+(F/2)*4
F=10N
hope u have understood
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