Question

A block of mass 2kg placed on a long frictionless table is pulled by a constant force F it is found to move 10m in 1st two seconds find magnitude of F

Answer 1

Answer:

since the table is frictionless,there is no opposing frictional force acting upon the block during its motion.

u=0 and t=2s and accn. of block a=F/m=F/2

then,

s=ut+1/2 at2

10=(0)2 +1/2 (F/2)(2)2

F=10N.

Answer 2

Explanation:

u= 0 and t=2s , m= 2kg

F=ma

a=F/m

a=F/2

s = ut +1/2at^2

10= 1/2+(F/2)*4

F=10N

hope u have understood