A block of mass 2kg rest on inclined plane at an angle of 30° with the horizandal the coefficient of friction between the block and the surface is 0.7 what will be the friction force acting on the block?
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A block of mass 2kg rest on inclined plane at an angle of 30° with the horizandal the coefficient of friction between the block and the surface is 0.7 what will be the friction force acting on the block
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1
Answer:
Given that,
Mass of the block, m=2 kg
Angle of inclination between the block and the horizontal line is given as :
θ=300
Also,
Coefficient of friction, μ=0.65
The force that tends to slide the body on the inclined plane can be given by,
f=mgsinθ
[A]F=2×9.8×0.5=9.8N
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