Question

A block of mass 2kg rests on a rough inclined plane making an angke of 30° with hthe horizontal the coefficient of static friction between the block and the plane is 0.The friction force on the block is

Answer 1

Answer:

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Answer 2

Given,

Mass of the body, m=2kg

Angle of inclination between the block and the horizontal line is,ø=30°

coefficient of friction ,ų= 0.7

The force that tend to slide the body on the inclined plane is=mg sinø

=mg sin30°

=2×10×1/2(g=10m/s^2)

=10N

the limiting friction between the block and the hrizontal plane is

=ųmg cos30°

=0.7×2×10×0.865

=12.11N

So friction is equal to the applied force(•.•applied force <limiting friction)

So, frictional force is 10N