Question

A block of mass 2kg slides on a rough surface with initial speed 2m/s it stops after travelling 20cm find work done by the Frictional force

Answer 1

Answer:

initial Kinetic energy , K

1

=

2

1

mv

1

2

=

2

1

×2×2=2 J

Final Kinetic energy , K

2

=0

Using work energy theorem we get

Work done by friction= Change in kinetic energy = K

2

−K

1

=−2 J

Explanation:

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Answer 2

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