Question

A block of mass 2kg slides on an inclined plane of angle 30

. The coefficient of friction is

3 / 2

. What force should be applied to the block so that it moves up with out any acceleration​

Answer 1

Answer:

Given:

➪M=2Kg μ= √3/2

➪mg sin 30° =2×10×1/2°10n

➪N=mg cos 30°=2×10×√3/2{10√3n

maximum value of friction is

➪ μn=√3/2×10√3

➪ 30/√2N f(s)

since f(s)=30/√2 >mg sin 30°

Therefore the body will not slip and no force is needed to be applied.

so this is your answer☝︎