Question

a block of mass 2kg was released slowly on a curved path from the height of 10 m if First Flight down and then teaches the point of 6 m what is the difference between its potential energy at the initial position and its final position​

Answer 1

Answer:

10 cm

Explanation:

Answer 2

Given,

• A block of mass 2kg.

• It is placed at a height of 10m.

To find,

Its potential energy when it is at a height of 6m

Solution,

Potential energy is the energy possessed by the body due to the virtue of its position with respect to some other body which is taken as reference.

Formula for the gravitational potential energy is $mgh$, where $g = 9.8m/s^{2}$.

Formula shows it only depends on height and mass of the body. Thus, the surface has no role to play in it. It can be curved or straight.

Here we are assuming that the surface is frictionless, else some potential energy will be lost in overcoming friction.

Initial potential energy = $mgh$

                                      $= 2*9.8*10J\\= 196J$

Final potential energy = $mgh$

                                      $= 2*9.8*6J\\= 117.8J$

Difference between initial and final potential energy

                                                 $= 196J - 117.6J\\= 78.4J$

Therefore, the difference between its potential energy at the initial position and its final position is $78.4J.$