Question

A block of mass 2m with constant velocity 3v hits another block of mass m which is at rest and stick to it. The velocity of the compound block

Answer 1

Answer:3v/4

Explanation:p(intital)= 3mv

P(final)=4mv'

P(intital)=P(final)

3mv=4mv'

V'=3v/4

Hopefully this is the correct answer

Answer 2

using conservation of momentum .......we know that

      FINAL momentum = INITIAL momentum

p(final) = total mass*velocity after collision

            = (2m+m)V'

             = 3mV'

P(initial) = m1v1+ m2v2

             = 2m(3v) + m(0)

             6mv

 therefore...........  3mV' = 6mv

               V' =  2v

velocity of compound block = 2 * velocity of first block