Question

a block of mass 3 kg is at rest on a rough inclined plane as shown in the figure the magnitude of net force exerted by the surface on the block will be​.

Answer 1

Step-by-step explanation:

f = mg

f = 3.10

f=30 Newton

Answer 2

Answer:

30N

Step-by-step explanation:

See it is on rough surface that friction also acts on it ... Hence the net  force ating is normal force + frictional force . Take x and y axis tilted i.e. along the surface. If you break the weight into components.. you will get weight components 15N and 15√3 N. normal force is 15 √3 N. and static friction as 15N. They are perpendicular so the resultant is √(15)square + (15√3)square i.e. 30N

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