Question

a block of mass 3 kg starts from rest from point P and slides down a fixed curved path as shown in figure if it reaches the bottom with speed for metre per second then work done against friction is( g=10m/s^2)? please help me frds.please​

Answer 1

A block of mass 3 kg starts from rest and slides down a advanced path in the shape of a quarter-circle of radius 2 m and reaches the bottom of path with a 4 m/s speed. If g is 10m/s2, the amount of work done against friction is

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ANSWER

Since, the gravitational force is conservative force. Hence, work done by it does not depend on path.

From the law of conservation

mgh=21mv2+Work done by friction ⇒Work done by friction =mgh−21mv2=3×10×2−21×3×16=60−24=36J

Answer 2

Answer:

law of conservation

use the law and solve it....