Question

A block of mass 37 kg rests on a rough
horteontal plane having coemetent of
statte netton 03. Find out the least
force required to just move the block
horisontally​

Answer 1

Given : μ

1=0.2 f2 =0.3 m

B=200 kg m

A=100 kg

Frictional force acting between blocks A and B f1 =μ 1 mAg

∴ f1 =0.2(100)(10)=200 N

Frictional force acting between block B and ground f2

=μ2(mA +mB )g

∴ f2 =0.3(100+200)(10)=900 N

Minimum force required to move block B, F=f

1 +f 2

⟹ F=200+900

=1100 N

hope it helps you ♥️♥️

with regards @ARSH