A block of mass 3kg is kept at a rough horizontal surface, μ=2√2. Find minimum force required to just move the block?
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Answer:
f=Fcos60
Normal force is N=−Fsin60o+mg
So, Fcos60o=μ(mg−Fsin600)
F=cos600+μsin600μmg=21+23123231(3×10)=320N
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