Question

a block of mass 4 kg falls on a spring from
a height 15 cm. If the spring constant of spring is
2000 N/m, maximum compression in the spring will
be: (take q = 10 m/s2)​

Answer 1

Answer:

77cm

Explanation:

Use the laws of conservation of energy.

Answer 2

The maximum compression in the spring will 0.08 m.

Explanation:

Use conservation of energy.

As block falls on a spring, the change in gravitational potential energy is  which became kinetic energy, then energy starts to transform to potential energy due to the displacement of the spring, as

$mgh=\frac{1}{2}kx^2$

Here, m is the mass of the block, h is the height, g is the acceleration due to gravity, k is the spring constant and x is maximum compression in the spring.

Given m = 4 kg, h = 15 cm = 0.15 m and k = 2000 N/m.

Substitute the given values, we get

  $4kg\times10m/s^2\times0.15m=\frac{1}{2}\times2000N/m\times x^2$

$x=\sqrt{\frac{6}{1000} }$

x = 0.0774 = 0.08 m

Thus, the maximum compression in the spring will 0.08 m.

#Learn More: compression in spring.

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