A block of mass 4 kg is kept on ground. The coefficient of friction between the block and the ground is 0.80. An external force of magnitude 30 N is applied parallel to the
ground. The resultant force exerted by the ground on the block is:
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Answer:
50N
Explanation:
this is because the maximum friction force that can act is 0.8×4×10=32 but the external force is just 30 N hence ground will exert 30 N in horizontal direction and there will be normal force equal tp weight of block i.e 4 ×10 = 40N
hence resultant force will be underoot of (30 square and 40 square)
answer is 50N
bro tell is this is correct ???
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