Question

a block of mass 4 kg is kept on ground the coefficient of the friction between the block and the ground is 0.8 and external force of magnitude 30 newton is applied parallel to the ground the resultant force exerted by the ground on the block is

Answer 1

Answer: The resultant force exerted by the ground on the block is zero.

Explanation:

Given that,

External force = 30 N

Coefficient of friction = 0.8

Mass = 4 kg

The frictional force is

$F_{f} = \mu mg$

$F_{f} = 0.8\times4\ kg\times9.8\ m/s^{2}$

$F_{f} = 31.4 N$

The frictional force is greater than the external force.

So, the block will not move.

Hence, the resultant force exerted by the ground on the block is zero.

Answer 2

"Given:

External force = 30 N

Coefficient of friction = 0.8

Mass = 4 kg

The frictional force is

$F_f =\mu mg$

$F_f = 0.8 \times 4 Kg \times 9.8 m/s^2$

$F_f = 31.4N$

The frictional force is greater than the external force.

So, the block will not move.

Hence, the resultant force exerted by the ground on the block is zero.

"Frictional force" is a force which occurs between two surfaces which depends on the surface of the object and the force acting on the objects. There are four different "types of friction" such as rolling, sliding, static, and fluid friction."