Question

a block of mass 4 kg is placed on a smooth surface . another block of mass 2 kg is placed over it the coefficient of friction between the two blocks is u= 0.5 . A force of 12 N is applied at the lower block as shown the force of friction between the blocks is​

Answer 1

Answer:

11th

Physics

Laws of Motion

Problems on Friction

A block A of mass 4kg is pl...

PHYSICS

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Asked on October 15, 2019 by

Sumitha Tikhade

A block A of mass 4kg is placed on another block B of mass 5kg and the block B rests on a smooth horizontal table. If the minimum force that can be applied on A so that both the blocks move together is 12N,find the maximum force that can be applied on B for the blocks to move together.

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ANSWER

In the first case, friction acts only between the 4kg block and the 5kg block.

As a result if 12N is the force required for both the blocks to move together,

In the second case, we consider both the blocks as a system and the force acting between them is an internal force.

Thus the ratio of the forces applied on a block to the mass of the block should be a constant.

4

12

=

9

F

Hence, the maximum force F = 27 N

solution