Physics, asked by vishavjasrotia9056, 7 months ago

A block of mass 4 kg is placed on the floor. The coefficient of static friction is 0.4. If a force of 12 N is applied on the block parallel to the floor, the force of friction between the block and floor (g = 10 ms-2) :

Answers

Answered by priyankapriyanka1980
1

Explanation:

f=k×m×g=0.4×4×10=16N

as the applied force is less than static friction it will not move

Similar questions