A block of mass 4 kg lies over a horizontal surface. Another block of mass 2 kg is placed over the first block. The normal reaction between the lower block and ground surface is (g = 10m * s ^ - 2)
Answers
Explanation:
The free body diagram of both the blocks are as shown in the figure.
a=
4+2
F
=
4+2
20
=
3
10
Using ΣF
x
=ma
x
For 4kg block, 20−N=4a=4×
3
10
N=20−
3
40
=
3
20
N
This can also be solved as below
For 2kg block, N=2a=2×
3
10
=
3
20
N
Here, N is normal reaction between the two blocks.
Answer:
60N
Explanation:
A body of mass= 4kg lies over a horizontal surface and another block of mass 2kg lies over the other body.
lets consider this 2 body system as 1 body system where the mass of the system will be the total mass of the 2 body system.
so the mass of the new system = 4kg+2kg = 6kg.
as given in the question acceleration due to gravity(g)= 10m/s²
as we know that in this system of 2 masses the weight of the whole system will be balanced by the Normal Reaction
so weight of the system= normal reaction between the lower block and system.
as weight = mass × g
and normal reaction= weight.
so Normal reaction= 6×10 =60N