Question

A block of mass 4kg is attached to a spring to a spring of spring constant 100 N/m. One end of spring is attached to the roof. initially the block is at rest. When released maximum speed attained by the blocks​

Answer 1

Answer:

The maximum length spring can get elongated under the weight of the mass is given by

x = $\frac{mg}{k}$

x = (4 x 9.8)/ 100 = 0.392m

Maximum speed occurs when all the spring potential energy is converted into kinetic energy

$\frac{1}{2} mv^{2} = \frac{1}{2} kx^{2} \\\\v = x\sqrt{\frac{k}{m} } \\\\v = 0.392(\sqrt{\frac{100}{4} } ) = 0.392(\sqrt{25} )$

v = 0.392 x 5 = 1.96m/s