Question

A block of mass 4kg is pressed against a wall by two perpendicular horizontal forces. F1 is prependicular to the wall and F2 is parallel to the wall. Us(coefficient) =0.8, Uk(coefficient) =0.5 and g=10ms?
For F1=75N and F2=30N and the block remains at rest on the wall then the force of friction is
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Answer 1

Answer:

Friction force due to wall is given as 50 N

Explanation:

As we know that the normal force due to wall is balanced by external force F1

so we have

$F_1 = N$

$N = 75 N$

now maximum possible static friction force on the block is given as

$F_s = \mu_s N$

$F_s = 0.8 (75)$

$F_s = 60 N$

now along vertical downward direction weight of the block which is given as

$W = mg$

$W = 4(10) = 40 N$

Horizontal force on the block applied externally is given as

$F = 30 N$

now net force parallel to the wall is given as

$F = \sqrt{30^2 + 40^2}$

$F = 50 N$

so here friction force will balance this net force

so we have

$F_f = 50 N$

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Topic : friction force

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Answer 2

Answer:

50N is considered to be the ans