Question

a block of mass 5 kg is at rest on a smooth horizontal surface water coming out of a pipe horizontally at the rate of 2 kg per second hits the Block with a velocity of 6 m per second the initial acceleration of the block is

Answer 1

Mass of block, M = 5kg
Block is at rest, U = 0
Water coming out of a pipe horizontally at the rate of 2 kg per second hits the Block with a velocity of 6 m per second.

In 1 second,
mass of water hitting the block, m = 2kg
Velocity, u = 6m/s

After hitting, let's say water and block move together as a system.
Velocity of block and water = V
Mass = M+m = 7kg

Now use the conservation of momentum of the system (per second)

(M+m)V = MU + mu

7 × V = 5×0 + 2×6

7V = 12

V = 12/7 m/s

So change in velocity of the block in one second is 12/7 m/s.

We know that acceleration is change in velocity per unit time.

Thus initial acceleration of block is 12/7 m/s^2.

Answer 2

Answer:

Explanation:

ANSWER

F= mv/t

​F =2×6=12N

F=12

F=ma

12=5a

a=2.4m/s .