Question

A block of mass 5 kg is kept on a rough horizontal surface (u = 0.5). A
horizontal force of 10 N is applied on the block. Frictional force acting
on the block is (g = 10 m s-2)
25 N
10 N
20 N
50 N​

Answer 1

10 N of static friction........

Answer 2

Answer:

Frictional force acting on the block is 25 N

Explanation:

Given that,

The mass of the block is 5kg which is kept on a rough horizontal surface with coefficient of friction 0.5.

$= > \mu = 0.5$

Also given that a horizontal force of 10N is applied on the block.The frictional force acting on the block is given by the relation

$f = \mu \: mg$

Substituting the known values in the above equation,we get

$f = 0.5 \times 5 \times 10 \\ = 25N$

Therefore,Frictional force acting on the block is 25 N

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