Question

A block of mass 5 kg is moving with velocith 8 m/s along east . If 10 N of force is applied along north then the final speed will be

Answer 1

Explanation:

1st we also find the A by

F=ma

10=5a

a=2

v²=u²+2as

s=v²-u²\2a

8²-0²/2×2

14 is ans

Answer 2

answer

8m/s

Explanation:

F=ma

F= m× v/t

10=5×8/t

10=40/t

t .10=40

t=40/10= 4sec

speed = distance/time

speed= velocity×time/time

(velocity=displacement/time )&

(distance = displacement)

speed = 8×4/4

speed = 8m/s