Question

A block of mass 5 kg is placed on a smooth table and tied from both ends by two masses 3 kg and 2 kg by means of light, inextensible strings passing through pulleys as shown. The tension in the string connecting 5 kg and 3 kg is

Answer 1

Answer:

answer is 27N.................

.

Answer 2

Answer:

The tension in the string connecting 5 kg and 3 kg is 30 N.

Explanation:

Given that,

Mass of block = 5 kg

Tied masses is given by

$m_{1}=3\ kg$

$m_{2}=2\ kg$

If the block of 5 kg is equilibrium.

We need to calculate the tension in the string connecting 5 kg and 3 kg

Using formula of tension

$T = mg$

Put the value into the formula

$T=3\times10$

$T = 30\ N$

Hence, The tension in the string connecting 5 kg and 3 kg is 30 N.